본문

Introduction to Qiskit | Coding with Qiskit 1.x | Programming on Quantum Computers

https://www.youtube.com/watch?v=Tk9LOL9--Y4

Welcome back to Coding with Qiskit, where IBM research scientist Dr. Derek Wang will get you up to speed with the latest developments in quantum computers for your own work. The foundation and focus will be on Qiskit 1.x, an open source and freely available software development kit that allows you to program useful quantum computational workflows, all the way from building quantum circuits and designing quantum algorithms, to submitting them to real quantum computers and orchestrating large-scale, complex work loads. With 1.0, we expect Qiskit to become much more stable, efficient and serve as the developer-ready software backbone for quantum computational workflow. Qiskit Resources:

Qiskit - https://qisk.it/cwq-install

Qiskit GitHub - https://github.com/qiskit/qiskit

Qiskit Slack - https://qiskit.slack.com

From Novelty to Utility : Quantum Paper Review -    • From Novelty to Utility - Quantum Pap...  

Read more at our blog:   / coming-soon-qiskit-1-0  

 How to Install Qiskit | Coding with Qiskit 1.x | Programming on Quantum Computers https://www.youtube.com/watch?v=dZWz4Gs_BuI

Hello World | Coding with Qiskit 1.x | Programming on Quantum Computers https://www.youtube.com/watch?v=93-zLTppFZw

Primitives | Coding with Qiskit 1.x | Programming on Quantum Computers https://www.youtube.com/watch?v=35ykEg3fG4c&t=5s

Dynamic Circuits | Coding with Qiskit 1.x | Programming on Quantum Computers https://www.youtube.com/watch?v=QDPtcwhpQkE&t=1s

Contributing to Qiskit | Coding with Qiskit 1.x | Programming on Quantum Computers https://www.youtube.com/watch?v=WGlRcZqENkE

 

[이 게시물은 bryanai님에 의해 2025-04-03 10:15:30 퀀텀 AI 스터디에서 이동 됨]

[이 게시물은 bryanai님에 의해 2025-04-03 10:18:33 AI강의사이트에서 이동 됨]

[이 게시물은 bryanai님에 의해 2025-04-06 23:04:22 퀀텀 AI 스터디에서 이동 됨]

[이 게시물은 bryanai님에 의해 2025-05-22 23:38:38 퀀텀 AI 스터디에서 이동 됨]

관련링크

• https://www.youtube.com/watch?v=Tk9LOL9--Y4 389회 연결

댓글목록 0

등록된 댓글이 없습니다.